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[MAN] memmove

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MEMMOVE

Section: Linux Programmer's Manual (3)
Updated: 2017-03-13
Index Return to Main Contents
 

NAME

memmove - copy memory area  

SYNOPSIS

#include <string.h>

void *memmove(void *dest, const void *src, size_t n);
 

DESCRIPTION

The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied from the temporary array to dest.  

RETURN VALUE

The memmove() function returns a pointer to dest.  

ATTRIBUTES

For an explanation of the terms used in this section, see attributes(7).
InterfaceAttributeValue
memmove() Thread safetyMT-Safe
 

CONFORMING TO

POSIX.1-2001, POSIX.1-2008, C89, C99, SVr4, 4.3BSD.  

SEE ALSO

bcopy(3), bstring(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)  

COLOPHON

This page is part of release 4.15 of the Linux man-pages project. A description of the project, information about reporting bugs, and the latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.


 

Index

NAME
SYNOPSIS
DESCRIPTION
RETURN VALUE
ATTRIBUTES
CONFORMING TO
SEE ALSO
COLOPHON

This document was created by man2html, using the manual pages.
Time: 04:45:41 GMT, September 16, 2022

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